3m^2=54

Solution for 3m^2=54 equation:

3m^2=54

We move all terms to the left:

3m^2-(54)=0

a = 3; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·3·(-54)
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{2}}{2*3}=\frac{0-18\sqrt{2}}{6}
=-\frac{18\sqrt{2}}{6}
=-3\sqrt{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{2}}{2*3}=\frac{0+18\sqrt{2}}{6}
=\frac{18\sqrt{2}}{6}
=3\sqrt{2}
$